Optimal. Leaf size=184 \[ \frac {\left (3 b^2 c^2+8 a d (3 b c+a d)\right ) x \sqrt {c+d x^2}}{8 c}+\frac {\left (3 b^2 c^2+8 a d (3 b c+a d)\right ) x \left (c+d x^2\right )^{3/2}}{12 c^2}-\frac {a^2 \left (c+d x^2\right )^{5/2}}{3 c x^3}-\frac {2 a (3 b c+a d) \left (c+d x^2\right )^{5/2}}{3 c^2 x}+\frac {\left (3 b^2 c^2+8 a d (3 b c+a d)\right ) \tanh ^{-1}\left (\frac {\sqrt {d} x}{\sqrt {c+d x^2}}\right )}{8 \sqrt {d}} \]
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Rubi [A]
time = 0.09, antiderivative size = 181, normalized size of antiderivative = 0.98, number of steps
used = 6, number of rules used = 5, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.208, Rules used = {473, 464, 201,
223, 212} \begin {gather*} -\frac {a^2 \left (c+d x^2\right )^{5/2}}{3 c x^3}+\frac {1}{12} x \left (c+d x^2\right )^{3/2} \left (\frac {8 a d (a d+3 b c)}{c^2}+3 b^2\right )+\frac {x \sqrt {c+d x^2} \left (8 a d (a d+3 b c)+3 b^2 c^2\right )}{8 c}+\frac {\left (8 a d (a d+3 b c)+3 b^2 c^2\right ) \tanh ^{-1}\left (\frac {\sqrt {d} x}{\sqrt {c+d x^2}}\right )}{8 \sqrt {d}}-\frac {2 a \left (c+d x^2\right )^{5/2} (a d+3 b c)}{3 c^2 x} \end {gather*}
Antiderivative was successfully verified.
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Rule 201
Rule 212
Rule 223
Rule 464
Rule 473
Rubi steps
\begin {align*} \int \frac {\left (a+b x^2\right )^2 \left (c+d x^2\right )^{3/2}}{x^4} \, dx &=-\frac {a^2 \left (c+d x^2\right )^{5/2}}{3 c x^3}+\frac {\int \frac {\left (2 a (3 b c+a d)+3 b^2 c x^2\right ) \left (c+d x^2\right )^{3/2}}{x^2} \, dx}{3 c}\\ &=-\frac {a^2 \left (c+d x^2\right )^{5/2}}{3 c x^3}-\frac {2 a (3 b c+a d) \left (c+d x^2\right )^{5/2}}{3 c^2 x}-\frac {1}{3} \left (-3 b^2-\frac {8 a d (3 b c+a d)}{c^2}\right ) \int \left (c+d x^2\right )^{3/2} \, dx\\ &=\frac {1}{12} \left (3 b^2+\frac {8 a d (3 b c+a d)}{c^2}\right ) x \left (c+d x^2\right )^{3/2}-\frac {a^2 \left (c+d x^2\right )^{5/2}}{3 c x^3}-\frac {2 a (3 b c+a d) \left (c+d x^2\right )^{5/2}}{3 c^2 x}-\frac {1}{4} \left (c \left (-3 b^2-\frac {8 a d (3 b c+a d)}{c^2}\right )\right ) \int \sqrt {c+d x^2} \, dx\\ &=\frac {1}{8} c \left (3 b^2+\frac {8 a d (3 b c+a d)}{c^2}\right ) x \sqrt {c+d x^2}+\frac {1}{12} \left (3 b^2+\frac {8 a d (3 b c+a d)}{c^2}\right ) x \left (c+d x^2\right )^{3/2}-\frac {a^2 \left (c+d x^2\right )^{5/2}}{3 c x^3}-\frac {2 a (3 b c+a d) \left (c+d x^2\right )^{5/2}}{3 c^2 x}-\frac {1}{8} \left (-3 b^2 c^2-24 a b c d-8 a^2 d^2\right ) \int \frac {1}{\sqrt {c+d x^2}} \, dx\\ &=\frac {1}{8} c \left (3 b^2+\frac {8 a d (3 b c+a d)}{c^2}\right ) x \sqrt {c+d x^2}+\frac {1}{12} \left (3 b^2+\frac {8 a d (3 b c+a d)}{c^2}\right ) x \left (c+d x^2\right )^{3/2}-\frac {a^2 \left (c+d x^2\right )^{5/2}}{3 c x^3}-\frac {2 a (3 b c+a d) \left (c+d x^2\right )^{5/2}}{3 c^2 x}-\frac {1}{8} \left (-3 b^2 c^2-24 a b c d-8 a^2 d^2\right ) \text {Subst}\left (\int \frac {1}{1-d x^2} \, dx,x,\frac {x}{\sqrt {c+d x^2}}\right )\\ &=\frac {1}{8} c \left (3 b^2+\frac {8 a d (3 b c+a d)}{c^2}\right ) x \sqrt {c+d x^2}+\frac {1}{12} \left (3 b^2+\frac {8 a d (3 b c+a d)}{c^2}\right ) x \left (c+d x^2\right )^{3/2}-\frac {a^2 \left (c+d x^2\right )^{5/2}}{3 c x^3}-\frac {2 a (3 b c+a d) \left (c+d x^2\right )^{5/2}}{3 c^2 x}+\frac {\left (3 b^2 c^2+24 a b c d+8 a^2 d^2\right ) \tanh ^{-1}\left (\frac {\sqrt {d} x}{\sqrt {c+d x^2}}\right )}{8 \sqrt {d}}\\ \end {align*}
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Mathematica [A]
time = 0.27, size = 119, normalized size = 0.65 \begin {gather*} \frac {1}{24} \left (\frac {\sqrt {c+d x^2} \left (24 a b x^2 \left (-2 c+d x^2\right )+3 b^2 x^4 \left (5 c+2 d x^2\right )-8 a^2 \left (c+4 d x^2\right )\right )}{x^3}-\frac {3 \left (3 b^2 c^2+24 a b c d+8 a^2 d^2\right ) \log \left (-\sqrt {d} x+\sqrt {c+d x^2}\right )}{\sqrt {d}}\right ) \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.10, size = 239, normalized size = 1.30
method | result | size |
risch | \(-\frac {\sqrt {d \,x^{2}+c}\, \left (-6 b^{2} d \,x^{6}-24 a b d \,x^{4}-15 b^{2} c \,x^{4}+32 a^{2} d \,x^{2}+48 a b c \,x^{2}+8 a^{2} c \right )}{24 x^{3}}+\ln \left (x \sqrt {d}+\sqrt {d \,x^{2}+c}\right ) d^{\frac {3}{2}} a^{2}+3 \ln \left (x \sqrt {d}+\sqrt {d \,x^{2}+c}\right ) \sqrt {d}\, a b c +\frac {3 \ln \left (x \sqrt {d}+\sqrt {d \,x^{2}+c}\right ) b^{2} c^{2}}{8 \sqrt {d}}\) | \(140\) |
default | \(b^{2} \left (\frac {x \left (d \,x^{2}+c \right )^{\frac {3}{2}}}{4}+\frac {3 c \left (\frac {x \sqrt {d \,x^{2}+c}}{2}+\frac {c \ln \left (x \sqrt {d}+\sqrt {d \,x^{2}+c}\right )}{2 \sqrt {d}}\right )}{4}\right )+a^{2} \left (-\frac {\left (d \,x^{2}+c \right )^{\frac {5}{2}}}{3 c \,x^{3}}+\frac {2 d \left (-\frac {\left (d \,x^{2}+c \right )^{\frac {5}{2}}}{c x}+\frac {4 d \left (\frac {x \left (d \,x^{2}+c \right )^{\frac {3}{2}}}{4}+\frac {3 c \left (\frac {x \sqrt {d \,x^{2}+c}}{2}+\frac {c \ln \left (x \sqrt {d}+\sqrt {d \,x^{2}+c}\right )}{2 \sqrt {d}}\right )}{4}\right )}{c}\right )}{3 c}\right )+2 a b \left (-\frac {\left (d \,x^{2}+c \right )^{\frac {5}{2}}}{c x}+\frac {4 d \left (\frac {x \left (d \,x^{2}+c \right )^{\frac {3}{2}}}{4}+\frac {3 c \left (\frac {x \sqrt {d \,x^{2}+c}}{2}+\frac {c \ln \left (x \sqrt {d}+\sqrt {d \,x^{2}+c}\right )}{2 \sqrt {d}}\right )}{4}\right )}{c}\right )\) | \(239\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.27, size = 177, normalized size = 0.96 \begin {gather*} \frac {1}{4} \, {\left (d x^{2} + c\right )}^{\frac {3}{2}} b^{2} x + \frac {3}{8} \, \sqrt {d x^{2} + c} b^{2} c x + 3 \, \sqrt {d x^{2} + c} a b d x + \frac {\sqrt {d x^{2} + c} a^{2} d^{2} x}{c} + \frac {3 \, b^{2} c^{2} \operatorname {arsinh}\left (\frac {d x}{\sqrt {c d}}\right )}{8 \, \sqrt {d}} + 3 \, a b c \sqrt {d} \operatorname {arsinh}\left (\frac {d x}{\sqrt {c d}}\right ) + a^{2} d^{\frac {3}{2}} \operatorname {arsinh}\left (\frac {d x}{\sqrt {c d}}\right ) - \frac {2 \, {\left (d x^{2} + c\right )}^{\frac {3}{2}} a b}{x} - \frac {2 \, {\left (d x^{2} + c\right )}^{\frac {3}{2}} a^{2} d}{3 \, c x} - \frac {{\left (d x^{2} + c\right )}^{\frac {5}{2}} a^{2}}{3 \, c x^{3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 2.01, size = 266, normalized size = 1.45 \begin {gather*} \left [\frac {3 \, {\left (3 \, b^{2} c^{2} + 24 \, a b c d + 8 \, a^{2} d^{2}\right )} \sqrt {d} x^{3} \log \left (-2 \, d x^{2} - 2 \, \sqrt {d x^{2} + c} \sqrt {d} x - c\right ) + 2 \, {\left (6 \, b^{2} d^{2} x^{6} + 3 \, {\left (5 \, b^{2} c d + 8 \, a b d^{2}\right )} x^{4} - 8 \, a^{2} c d - 16 \, {\left (3 \, a b c d + 2 \, a^{2} d^{2}\right )} x^{2}\right )} \sqrt {d x^{2} + c}}{48 \, d x^{3}}, -\frac {3 \, {\left (3 \, b^{2} c^{2} + 24 \, a b c d + 8 \, a^{2} d^{2}\right )} \sqrt {-d} x^{3} \arctan \left (\frac {\sqrt {-d} x}{\sqrt {d x^{2} + c}}\right ) - {\left (6 \, b^{2} d^{2} x^{6} + 3 \, {\left (5 \, b^{2} c d + 8 \, a b d^{2}\right )} x^{4} - 8 \, a^{2} c d - 16 \, {\left (3 \, a b c d + 2 \, a^{2} d^{2}\right )} x^{2}\right )} \sqrt {d x^{2} + c}}{24 \, d x^{3}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [B] Leaf count of result is larger than twice the leaf count of optimal. 352 vs.
\(2 (168) = 336\).
time = 6.30, size = 352, normalized size = 1.91 \begin {gather*} - \frac {a^{2} \sqrt {c} d}{x \sqrt {1 + \frac {d x^{2}}{c}}} - \frac {a^{2} c \sqrt {d} \sqrt {\frac {c}{d x^{2}} + 1}}{3 x^{2}} - \frac {a^{2} d^{\frac {3}{2}} \sqrt {\frac {c}{d x^{2}} + 1}}{3} + a^{2} d^{\frac {3}{2}} \operatorname {asinh}{\left (\frac {\sqrt {d} x}{\sqrt {c}} \right )} - \frac {a^{2} d^{2} x}{\sqrt {c} \sqrt {1 + \frac {d x^{2}}{c}}} - \frac {2 a b c^{\frac {3}{2}}}{x \sqrt {1 + \frac {d x^{2}}{c}}} + a b \sqrt {c} d x \sqrt {1 + \frac {d x^{2}}{c}} - \frac {2 a b \sqrt {c} d x}{\sqrt {1 + \frac {d x^{2}}{c}}} + 3 a b c \sqrt {d} \operatorname {asinh}{\left (\frac {\sqrt {d} x}{\sqrt {c}} \right )} + \frac {b^{2} c^{\frac {3}{2}} x \sqrt {1 + \frac {d x^{2}}{c}}}{2} + \frac {b^{2} c^{\frac {3}{2}} x}{8 \sqrt {1 + \frac {d x^{2}}{c}}} + \frac {3 b^{2} \sqrt {c} d x^{3}}{8 \sqrt {1 + \frac {d x^{2}}{c}}} + \frac {3 b^{2} c^{2} \operatorname {asinh}{\left (\frac {\sqrt {d} x}{\sqrt {c}} \right )}}{8 \sqrt {d}} + \frac {b^{2} d^{2} x^{5}}{4 \sqrt {c} \sqrt {1 + \frac {d x^{2}}{c}}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 1.06, size = 262, normalized size = 1.42 \begin {gather*} \frac {1}{8} \, {\left (2 \, b^{2} d x^{2} + \frac {5 \, b^{2} c d^{2} + 8 \, a b d^{3}}{d^{2}}\right )} \sqrt {d x^{2} + c} x - \frac {{\left (3 \, b^{2} c^{2} \sqrt {d} + 24 \, a b c d^{\frac {3}{2}} + 8 \, a^{2} d^{\frac {5}{2}}\right )} \log \left ({\left (\sqrt {d} x - \sqrt {d x^{2} + c}\right )}^{2}\right )}{16 \, d} + \frac {4 \, {\left (3 \, {\left (\sqrt {d} x - \sqrt {d x^{2} + c}\right )}^{4} a b c^{2} \sqrt {d} + 3 \, {\left (\sqrt {d} x - \sqrt {d x^{2} + c}\right )}^{4} a^{2} c d^{\frac {3}{2}} - 6 \, {\left (\sqrt {d} x - \sqrt {d x^{2} + c}\right )}^{2} a b c^{3} \sqrt {d} - 3 \, {\left (\sqrt {d} x - \sqrt {d x^{2} + c}\right )}^{2} a^{2} c^{2} d^{\frac {3}{2}} + 3 \, a b c^{4} \sqrt {d} + 2 \, a^{2} c^{3} d^{\frac {3}{2}}\right )}}{3 \, {\left ({\left (\sqrt {d} x - \sqrt {d x^{2} + c}\right )}^{2} - c\right )}^{3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {{\left (b\,x^2+a\right )}^2\,{\left (d\,x^2+c\right )}^{3/2}}{x^4} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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